Reimplementing the Mac SE's BBU

Zane Kaminski

Administrator
Staff member
Founder
Sep 5, 2021
372
610
93
Columbus, Ohio, USA
Reimplementing the BBU has been a much-discussed topic on here. Whenever it comes up, I always suggest that we should be focusing not on a form and function replacement for the BBU but a redesigned Mac SE motherboard using modern RAM and FPGA to implement the BBU and RAM. Thanks to @Kai Robinson 's Mac SE Reloaded, we have the mechanical design for an SE board; now all we need to do is swap out the RAM, BBU, and other supporting components for a new implementation using modern FPGA and SDRAM.

Now I have to say right off the bat that I am not able to pursue this project to completion, but I have had the design for the RAM controller and video output subsystem of the BBU in my head for a while. So here's my attempt to write down my thoughts on how to implement this portion of the BBU. I want to emphasize that my aim here in reimplementing the BBU is to eliminate legacy/hard-to-find components from the design and instead replace them with new-manufacture (harder to solder) FPGAs and 74xx chips. The total number of chips and soldered pins on this implementation of the BBU will be higher than in the Mac SE, and it will use fine-pitch surface-mount components. That's the trade-off associated with using new chips! So we have to accept the downsides of more chips, surface-mount, and more pins if we wanna replace the BBU in the way I am describing. And I am just trying to replace the BBU and associated circuitry, not the SWIM (floppy chip), ADB microcontroller, RTC+PRAM chip, etc. We can however replace the Sony sound chip and GLU because they're really easy to reimplement, either in 74xx or in the FPGA (if we have enough pins). If someone helps complete this project then we can move on to redoing the SWIM and other I/O chips but I think first things first, we need to do the BBU.

Right away, one of the supporting components we wanna eliminate is the 15.6672 MHz oscillator since it's somewhat rare. To generate this clock without an oscillator of the exact same frequency, we need an FPGA with a PLL. I like Lattice MachXO2. The LCMXO2-1200HC-4TG144C is in TQFP-144 package and has plenty of logic and 104 I/O pins (excluding JTAG). We supply the FPGA with a 25 MHz clock (very common frequency) and we can generate 15.6672 MHz using the internal PLL. Great!

Next on the list to eliminate is legacy DRAM. We can use a single SDRAM chip. 8 MB is a common size of SDRAM these days and prices before the chip shortage were under $0.50 each in 100ish unit quantity. Since the Mac SE's RAM size is only 4 MB, we can also eliminate costly parallel ROM chips, instead opting to copy the contents of a cheap serial flash ROM into RAM at startup and serving the ROM reads out of RAM.

We need to connect to every signal the BBU connects to and do functionally identical stuff on all of the output lines. Nominally I would draw a block diagram but I am just trying to get this basic thought out there so that someone else can maybe do a layout. So let me just list the pins the FPGA needs to connect to:
Code:
Clock (4)
(1)    CLK_IN (25 MHz)
(3)    C16M, C8M, C4M

68k (52)
(23)    A[23:1] (68k address bus)
(16)    D[15:0] (SDRAM data bus  68k data bus)
(2)    /DOE, DDIR (data bus buffer control)
(4)    /AS, /LDS, /UDS, R/W (68k outputs)
(2)    /DTACK, /VPA, /BERR (68k cycle termination signals)
(3)    /RESETi, /RESETo (reset in and out)
(2)    /IPL[1:0] (68k interrupt signals)

PDS (2)
(2)    /PMCYC, /EXT.DTK

SDRAM (22)
(14)    BA[1:0], RA[11:0] (SDRAM address bus)
(2)    DQMH, DQML (SDRAM low/high byte mask)
(5)    /CS, CKE, /RAS, /CAS, /WE (SDRAM control signals)
(1)    CLK (SDRAM clock)

Video (3)
(3)    HSYNC, VSYNC, VID

Sound + Brightness/Disk Speed (7)
(2)    SND, PBL

I/O Select (7)
(5)    SELSCC, SELSWIM, SELSCSI, SELVIA, EXTPDS
(2)    /RD (SCC), /WR (SCC)

SCSI Pseudo-DMA (3)
(3)    /EOP, DACK, DRQ

VIA Interface (3)
(2)    PB7, PA6
(1)    IRQ

Flash (4)
(4)    /CS, SCK, MOSI, MISO

JTAG (3)
(4)    TCK, TDI, TMS, TDO
If it's not obvious from the pinout, we are going to connect to the entire 68k address bus, unlike the BBU which has a multiplexed connection to the address bus. Regarding the data bus, we are sharing it between the SDRAM, FPGA, and 68k, just like the BBU does. All signals coming from the FPGA and connecting to the 68k bus need level-shifting buffers since the FPGA is not 5V-tolerant. 74AHC245 is a good choice for these.

Now let's start implementing. We are going to implement clock generation, the SDRAM command sequence, and then video, in that order.

Internal to the FPGA, we are going to generate a 31.3344 MHz clock from the 25 MHz clock. This "C32M" clock will be used to run the state machine and SDRAM. But then we need to output some clocks. Referring to the list of pins, we need to output 15.6672 MHz (C16M), 7.8336 MHz (C8M) and 3.9168 MHz (C4M) clocks. I see this "C3.7M" stuff in the Bomarc schematics. Huh? I thought it was is actually a 3.9168 MHz division of the main clock.

Alright, my strategy for the clock is as follows. First we are going to make a 4-bit binary counter, called S[3:0]. It will count from 0-15. We are going to use this counter to create the clock signals. Now in the Mac SE, the C16M clock is the sort of "master clock" in the system and all of the other clocks are registered outputs clocked by C16M. That means all of the other clocks will be slightly delayed compared to C16M since their toggling is a consequence of the C16M rising edge. According to "Designing Cards and Drivers," this delay can be up to 30 nanoseconds. So no matter what, we need to make sure the C8M and C4M clocks' rising edges are delayed a a good bit compared to C16M, but not more than 30ns. Okay, check this timing diagram:
Screen Shot 2022-04-15 at 2.23.12 AM.png

I've just expanded the the S[3:0] count sequence. From this it's really easy to get the three clock signals. C16M is S[0] inverted, C8M is S[1] but delayed one half clock cycle, and C4M is S[2] again delayed half a clock. So:
Screen Shot 2022-04-15 at 2.24.31 AM.png

Great, we have our clock signals. We just send these out of the FPGA as-is. They all have the right frequency and C4M/C8M are delayed half a clock so they will come out of the FPGA approximately 16 nanoseconds (half a 31.3344 MHz clock period) after C16M. This delay is accomplished by sending the S[2] and S[1] bits through a falling edge-triggered register.

The verilog for this is quite simple:
Code:
reg [3:0] S;
output reg C8M;
output reg C4M;
always @(posedge C32M) begin
    S <= S+1;
    C16M <= S[0];
end
always @(negedge C32M) begin
    C8M <= S[1];
    C4M <= S[2];
end

Moving on, we need to design the RAM controller. We have to sort of copy this diagram of the BBU functionality from "Designing Cards and Drivers":
1650004074746.png

So basically, the BBU runs at 15.6672 MHz and repeats two different 8-state patterns. First the BBU allows the video circuitry to read RAM, then the BBU allows the MC68k to read RAM three times. If MC68k misses the RAM access window, it has to wait until the next opportunity to access RAM. After one video access and then three CPU access windows, the cycle repeats. Also, during vertical and horizontal blanking, the video access window is given to the CPU.

Let me elaborate a little bit on the "RAM access window." The Apple diagram is a little bit misleading because it shows /AS falling specifically during S2. If each RAM access took four clocks, it would line up this way, but sometimes, MC68k takes a non-multiple-of-4 clock cycles between accesses. In actuality, MC68k can assert /AS after any C8M rising edge, i.e. in any even-numbered state. What the diagram is supposed to mean is that if /AS falls in a state other than S2, the BBU doesn't respond to it until the next S2, so it would be as if /AS only falls during S2. Subtly different though and we should not have an assumption in our controller logic on /AS only falling in our state corresponding to S2.

Okay, so the Apple diagram has 8 states per RAM access, but we have a 31.3344MHz clock (twice as fast) so we need 16 states. We already have this with the S[3:0] clock counter! So just like in the above image of the BBU's functionality, we need to define the operation sequence for video reads, CPU reads, and CPU writes. This will get encapsulated into the RAM controller block of our system. One thing the RAM controller block is not responsible for is deciding whether the current RAM access cycle should be for CPU or video access. That will be left to the client of the RAM controller. Okay I tried writing the operating sequence for video access first:
Screen Shot 2022-04-15 at 3.11.11 AM.png

To give some context, VID/CPU is a signal supplied by the client of the RAM controller indicating whether the current sequence should be for video or CPU access. VID/CPU should be valid from S5-S14 but can change between S15-S4. The client of the RAM controller also must provide the address for the video access but I have not included addressing stuff because it's pretty much just a straightforward consequence of the command issuance. So referring to the above diagram, RCMD and RCKE form the SDRAM command. CKE is "clock enable." Basically, if CKE is 0, the next clock pulse is ignored by the SDRAM. So CKE is 0, before issuing a command, we need to issue a NOP CKE to wake up the SDRAM chip. So we start in our S4 by issuing a NOP CKE command to the SDRAM to wake it up after the clock being disabled previously. Then in S5 we check VID/CPU. For this timing diagram, we are assuming it's 1, i.e. video access, so we issue an ACTivate command to open the correct row for the video access. We are assuming a CAS latency of 2 for the SDRAM so read data comes out of the RAM one clock after the read command is executed. We need to read two 16-bit data buses worth of data for the video access so we issue two RD commands at the end of S6 and S7 but we manipulate the CKE pin and issue some NOPs to slow the data rate down to make a large capture window so the FPGA can clock in the data. So at the end of S9 and S11, the data has been stable for a clock cycle or so, so, we shift in the video data coming out of the RAM. Then by S12, we have VD[31:0] corresponding to the 32 bits of video data just read from RAM. Not shown explicitly is precharging. The second read in the sequence oughta have the auto-precharge bit set so that a precharge is executed in S10 ahead of the REFresh command issued in S11 (and executing in S12). The rest of the time is just NOP CKD to disable the SDRAM clock and save power..

Moving on, we have similar diagrams for read and write CPU accesses. Here's reading:
Screen Shot 2022-04-15 at 3.11.33 AM.png

And writing:
Screen Shot 2022-04-15 at 3.12.26 AM.png

There isn't much to add here other than that precharge isn't explicitly shown. The RD and WR commands oughta be of the auto-precharge type. also notice the RDDIR and /RDOE signals. These control the '245 buffers between the 68k data bus and the FPGA+SDRAM data bus. We have to enable the output at the right times for reading and writing and also set the direction correctly. For the video operations previously discussed /RDOE is always 1 to isolate the video read data from the 68k bus.

So the idea here is that we are checking /AS and VID/CPU at the end of S5. Since the above diagrams are for the CPU access case, we check /AS, and if it's 0, then we go into the RAM read/write sequence. Of course if /AS is 1 then we need an idle sequence. Something like this:
Screen Shot 2022-04-15 at 3.10.41 AM.png

Just do nothing...

Notice in all four cases (read/write/idle/video) the slight difference in the assumption on /AS and VID/CPU. In all cases, VID/CPU should be stable between S5 and S14. But the assumption on /AS differs. For the idle case, /AS should be checked and saved during S5, since it could go low in the future and we would not want to execute the second half of the RAM access sequence but not the first. But for the read and write cases, if /AS is low in S5, it is assumed not to change until the end of the RAM access cycle.

Notice also how although the RAM controller makes demands of its client (not allowing VID/CPU or /AS to change at the wrong times) but also provides certain guarantees. If VID/CPU and /AS are set for a CPU access at the right time, the operation will complete in a specified number of cycles. Therefore the RAM controller doesn't have to be bothered generating some kind of proto-DTACK signal and the external circuitry can just generate it based on the guaranteed completion of the RAM operation.

Oh also the /AS sent to the RAM controller should be further gated with the RAM/ROM select signal such that /AS as seen by the RAM controller doesn't fall when I/O devices are being accessed.

I won't write all the code for the RAM controller since it's quite simple, basically just a big if statement based on S[3:0], VID/CPU, /AS, and R/W. Here's a rough sketch:
Code:
always @(posedge C32M) begin
    case (S[3:0]):
        0: // issue NOP CKD
        1: // ...
        2: // ...
        3: // ...
        4: // issue NOP CKE
        5: // Check /AS, VID/CPU and issue ACT or NOP accordingly
        6: // issue RD or NOP accordingly
        7: // ...
        ...
    endcase
end
Obviously I have omitted the specifics but it's pretty easy to write the code looking at the timing diagrams. It's just a big if statement which issues the commands depending on the state number, /AS, VID/CPU, and R/W.

Okay so we have basically implemented clocking and SDRAM control, now let's focus back on video.

The Mac SE's video pixel clock is the same C16M clock as we have generated. The machine has a 512x342 active screen resolution but the total including the retrace periods is 704x370. Notice how in the BBU timing diagram, there were some eight-state cycles repeated four times for a total of 32 states. And conveniently, 704 is divisible by 32. So basically the BBU's RAM access state counter runs off the low bits of the video horizontal counter. Now in our system, we are running from C32M so we need 1408 horizontal states (704x2) and the unit of repetition is 64 states long but it's basically the same thing.

So we extend the S[3:0] counter into HS[10:0] which will count from 0-1407. Here's the verilog:
Code:
reg [10:0] HS;
wire [3:0] S = HS[3:0];
always @(posedge C32M) begin
    if (HS==1407) HS <= 0;
    else HS <= HS+1;
end

Now we need the vertical counter which goes from 0-369:
Code:
reg [8:0] VS;
always @(posedge C32M) begin
    if (HS==1407) begin
        if (VS==369) VS <= 0;
        else VS <= VS+1;
    end
end

With these, we can generate the HSYNC and VSYNC signals. Just need to know the H and V coordinates where the sync pulses begin and end:
Code:
reg nHSYNC, nVSYNC;
always @(posedge C32M) begin
    if (HS==HSYNC_HSTART && VS==HSYNC_VSTART) nHSYNC <= 0;
    else if (HS==HSYNC_HEND && VS==HSYNC_VEND) nHSYNC <= 1;
 
    if (HS==VSYNC_HSTART && VS==VSYNC_VSTART) nVSYNC <= 0;
    else if (HS==VSYNC_HEND && VS==VSYNC_VEND) nVSYNC <= 1;
end

Now we are going to define the timing relationship between the horizontal/vertical counters and the RAM controller by deciding when to change the VID/CPU signal. Let's define VS states 0-341 as the active lines. During each line, let's fetch video data during HS0-15, HS64-79, HS128-143, ..., HS960-975. So during those states, VID/CPU will be 1, telling the RAM controller to do a video access. Otherwise, VID/CPU will be 0 and the MC68k can access the RAM. Now here's the tricky part. Video data becomes available in S12 of a video access cycle, so we will be putting out the active pixels of a line during the even states from HS12-1034. You'd think it would be HS0-1024 or something but it's actually a bit later since the video data is only available 3/4 of the way (S12) through the video read cycle. Here's the code:
Code:
reg VIDnCPU;
always @(posedge C32M) begin
    if (S[3:0]==0) begin
        //FIXME: < operator is bad!!
        if (VS < 342 && HS[5:4]==0 && HS < 1024) VIDnCPU <= 1;
        else VIDnCPU <= 0;
    end
end
Note here that we have chosen the numbering of the active pixel states arbitrarily. This is okay but we need to make sure to set the HSYNC/VSYNC start/end coordinates accordingly since they will be relative to the active pixel coordinates HS12-1034 / VS0-341. Another issue in the code is the use of the "<" operator. Less-than is quite a heavy operation in a small FPGA! We should switch to something where range flags are set/cleared at certain HS/VS values. Equivalence checks require much less logic to implement than less-than and greater-than checks.

Now that we have VID/CPU implemented, let's implement the 1-bit video pixel value output:
Code:
reg [31:0] VD_shift;
assign VIDOUT = VD_shift[0];
always @(posedge C32M) begin
    if (HS >= 12 && HS <= 1036) begin
        if (HS[3:0]==12) VD_shift[31:0] <= VD[31:0];
        else VD_shift[31:0] <= {1'b0, VD_shift[31:1]};
    end else VD_shift[31:0] <= 32'hFFFFFFFF;
end
We could save some register bits in the FPGA by combining the VD_shift register with the VD register from the RAM controller. And also this code has the < operator problem I mentioned previously but we can correct that later.

Alright I'm tired so that's all for now. Hopefully this all makes enough sense. There are some more parts to the BBU such as /DTACK and /VPA generation, chip select generation, SCSI pseudo-DMA, audio DMA, etc. which I have not made a stab at implementing. But the RAM controller and the relationship with the video circuitry is the most complex and is sort of the central part of everything else in the BBU.

Next maybe I will write about implementing the chip select signals, /DTACK and /VPA generation, etc.

Anyone wanna do the layout? I will perfect the FPGA code I've written about here if someone designs a board.
 
Last edited:

alxlab

Active Tinkerer
Sep 23, 2021
287
312
63
www.alxlab.com
I was just thinking that at some point when you start replacing/overriding so much like this:

1650037513401.png


you're probably better off just making a new mainboard lol.

I was actually thinking it would be cool to just modify Kai's SE Reloaded board to have a single 72-pin ram slot and replace all the through hole caps and resistors with SMDs, but this would really take it to the next level.

Was curious to know if you had any thoughts on this already -> The other thing that was bugging me for a while was the 4MB ram limitation due to how the ROM divides up the address space. Do you think it's even remotely possible to get the Macintosh Portable ROM to work on an SE board? It's the only 68000 series Mac that can access 9MB of RAM total, but obviously there's other hardware differences like using SRAM instead of DRAM, having battery management, using an LCD screen, etc.
 

cy384

New Tinkerer
Nov 18, 2021
18
18
3
USA
www.cy384.com
I'm willing to put up the cash to sponsor someone who wants to implement the hardware for this (the BBU/RAM replacement). I think we as a community are very close to being able to make new Mac SE clones with exclusively modern parts (minus the CRT, plus modern video out, etc.), and I really want to see that happen.
 
  • Like
Reactions: Zane Kaminski

Zane Kaminski

Administrator
Staff member
Founder
Sep 5, 2021
372
610
93
Columbus, Ohio, USA
Was curious to know if you had any thoughts on this already -> The other thing that was bugging me for a while was the 4MB ram limitation due to how the ROM divides up the address space. Do you think it's even remotely possible to get the Macintosh Portable ROM to work on an SE board? It's the only 68000 series Mac that can access 9MB of RAM total, but obviously there's other hardware differences like using SRAM instead of DRAM, having battery management, using an LCD screen, etc.
I just don't think the Portable ROM is "universal" like the later Mac II ROMs are. I'm not sure it can boot the SE without major modifications. This would make sense since the SE and Portable have totally different memory maps, so what would be the point of Apple making the Portable ROM work on the SE? To be useful they would have had to have a Prototype with the "SE" chipset but the RAM and ROM in the address space like the Portable.

I'm willing to put up the cash to sponsor someone who wants to implement the hardware for this (the BBU/RAM replacement). I think we as a community are very close to being able to make new Mac SE clones with exclusively modern parts (minus the CRT, plus modern video out, etc.), and I really want to see that happen.
Ooh wow, nice offer! But we are a little bit further from totally eliminating legacy chips than might appear. There's still the following chips which we don't have an implementation for:

SWIM floppy chip
Shouldn't require too many FGPA resources to but getting it cycle-accurate might be hard. Big Mess O' Wires has his Yellowstone disk controller which has an IWM implementation (but not SWIM?). But he might not want license it with the kind of open license that the SE project oughta have.

ADB MCU
There's a PIC microcontroller on the board which runs at ~4 MHz and is responsible for talking to the ADB keyboard and mouse. Someone has decapped the chip and extracted the ROM. Can this just run on a new PIC? Or will we have to disassemble it and tweak it to run on a new PIC? I'm an AVR guy lol, no experience with PICss so someone else will have to advise about this.

RTC+PRAM chip
Basically it has an SPI interface (bit-banged by the VIA) to the RTC clock registers and the PRAM data. We have seen attempts to implement this in a (coincidentally pin-compatible) ATtiny MCU but the results have been flaky at best, I understand. One major issue is that the RTC's SPI bus is specced for multiple MHz. If we try to emulate it via bit-banging, the result will be quite slow and we won't be able to make the timings guaranteed by the datasheet. Of course, the Mac SE operates the RTC by bit-banging through the VIA, so the maximum speed at which the RTC is actually operated is under 1 MHz. Nevertheless it may be hard or impossible to make the bit-banging approach work even at 1 MHz. Maybe a faster microcontroller could make the it work, and of course it will have to have some kind of battery backup clock/SRAM facility. Sadly we're still in the STM32 shortage so it's not clear what chip to use. If the bit-bang approach is too slow, we can keep the RTC and PRAM in an MCU and transfer the PRAM data and current time to an FPGA during startup. That way the FPGA can serve the data at a higher speed than the MCU would be capable of.

6522 VIA
Pretty well understood... we can implement it in an FPGA and there's probably an existing soft core. However it's still available from WDC for $10.

8530 SCC
Probably harder than the VIA to implement but doable. Still available from Zilog for $10 though.

5380 SCSI chip
Even harder than the VIA, plus our implementation oughta solve the SCSI drive strength/slew rate issue that nobody attends to in modern SCSI designs. I think Zilog sells their 5380 implementation? Not sure.

Sony sound chip
The Sony chip does power-on reset plus it filters the PWM sound into the audio signal with adjustable volume. Easy to implement with other chips.


Hopefully we can one day implement all of this stuff in a second "Mac southbridge" or "Mac super I/O" FPGA alongside the BBU clone FPGA. It could all be done together in the same FPGA but that would require a BGA chip because of the pin count. I figure it's better to partition it into the BBU "northbridge" and I/O "southbridge" and use two TQFP-144 chips. But for starters, I think we should begin with the BBU since it's the rarest ASIC on the SE and I consider it pretty easy to implement compared to the I/O stuff. I/O is a bit "real-world" so getting it perfect is harder than perfecting the processor bus/RAM/video functionality of the BBU.
 
  • Like
Reactions: cy384

cy384

New Tinkerer
Nov 18, 2021
18
18
3
USA
www.cy384.com
Yeah, that largely meshes with my understanding of the situation.
  • SCSI chip: is the Z53C8003VSG compatible? seems like Zilog still makes it? Mouser has some, anyway.
  • ADB chip: I've been following the ADB PIC discussion, seems like they're pretty close, maybe one or two mysteries away from success. It's a small amount of code, could maybe be rewritten for some other MCU if nobody can get it working on the nearest still-available PIC.
  • SWIM: possibly doable but weird solution: hack the ROM? to make the OS always report no floppy drives attached and just not have any hardware floppy support
My opinion is that an ~80% functional clone that will boot Mac OS would be a huge coup, even minus some functionality.
 
Last edited:
  • Like
Reactions: Zane Kaminski

Zane Kaminski

Administrator
Staff member
Founder
Sep 5, 2021
372
610
93
Columbus, Ohio, USA
Yeah, that largely meshes with my understanding of the situation.
  • SCSI chip: is the Z53C8003VSG compatible? seems like Zilog still makes it? Mouser has some, anyway.
  • ADB chip: I've been following the ADB PIC discussion, seems like they're pretty close, maybe one or two mysteries away from success. It's a small amount of code, could maybe be rewritten for some other MCU if nobody can get it working on the nearest still-available PIC.
  • SWIM: possibly doable but weird solution: hack the ROM? to make the OS always report no floppy drives attached and just not have any hardware floppy support
My opinion is that an ~80% functional clone that will boot Mac OS would be a huge coup, even minus some functionality.
Z53C8003 seems compatible but I am not intimately familiar with the workings of the 5380 so I can't like, look at the datasheet and see if anything is inconsistent. We should just try it lol. As for the SWIM, we can do one better, just emulate a SWIM connected to nothing. Should be easy since who cares about cycle-accuracy if it just looks like nothing is connected. We could also put the microSD interface I wrote you about on the board. Wouldn't that be nice to have!




One frustrating issue with my current BBU concept is that the BBU "northbridge" can't share the level-shifting buffers for the data bus with a possible "southbridge" I/O chip. This is because the BBU turns off the data bus buffers during a video read operation, so another chip can't just be put on the level-shifted data bus without some additional cooperation with the BBU FPGA.

Also the architecture I described in my first post can implement RAM, but I realized it falls a little bit short in that it can't implement ROM with cycle-exact timing. The issue is that I copied the BBU timings too closely while sort of hand-waving the details of the ROM-in-RAM implementation. Consequently ROM access is subject to the same "RAM access window" phenomenon as RAM. This is unlike the SE, where ROM can be accessed at any time. I will be updating the state machine design soon to address this and hopefully the above-mentioned I/O buffer sharing problem too.
 
  • Like
Reactions: cy384

max1zzz

Moderator
Staff member
Sep 23, 2021
233
566
93
27
Z53C8003 seems compatible but I am not intimately familiar with the workings of the 5380 so I can't like, look at the datasheet and see if anything is inconsistent. We should just try it lol.
Pinout is different between the 5380 and 53C80 so it's not a straight swap. I just ordered one though and might try and rats-nest it onto the repro IIcx board and see what happens
 

tevruden

New Tinkerer
Mar 9, 2022
1
0
1
Referring to the list of pins, we need to output 15.6672 MHz (C16M), 7.8336 MHz (C8M) and 3.9168 MHz (C4M) clocks. I see this "C3.7M" stuff in the Bomarc schematics. Huh? I thought it was is actually a 3.9168 MHz division of the main clock.
Since 3.9168MHz would be the number for C4M on previous logic boards but the divisions between high and low states as measured from actual chips aren't as periodic as the diagrams would suggest, it might be a discrepancy annotating what was measured?
 

Zane Kaminski

Administrator
Staff member
Founder
Sep 5, 2021
372
610
93
Columbus, Ohio, USA
Since 3.9168MHz would be the number for C4M on previous logic boards but the divisions between high and low states as measured from actual chips aren't as periodic as the diagrams would suggest, it might be a discrepancy annotating what was measured?
In retrospect I think it's more like a 4/17 "uneven" or "jittery" division of the main clock to support the AppleTalk (and industry-standard) 230.4 kbaud rate for the serial port since (15.6672) * (4/17) * (1/16) is exactly 230,400.