It looks like the jumpers follow a predictable binary pattern
EO=+1MB
E1=+2MB
E2=+4MB
E3=+8MB
E4=unknown
So, to get +8MB (9 in total with motherboard 1MB), pull jumper E3. To get +7MB (8 in total), keep E3 but pull E2+E1+E0. This explains why the board with 2 megabytes already soldered to it...